What is the amplitude of f(x)=-4-5cos(2x-pi) ?

The amplitude of f(x)=-4-5cos(2x-pi) is 5

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amplitude of f(x)=-4-5cos(2x-pi)

amplitude

f (x) = - 4 - 5 cos (2 x - π)

5

Solution steps

f (x) = - 4 - 5 cos (2 x - π), A = - 5

Therefore, the amplitude |A| is

5

5

f (x) = - (4)^{x + 3}

f (x) = (x + 1)^{2}

- x^{2} + 6 x - 5

- x^{2} + 4 x - 7

f (x) = \frac{( x ^{2} + 3 )}{x ( 5 x - 1 )}

What is the amplitude of f(x)=-4-5cos(2x-pi) ?
The amplitude of f(x)=-4-5cos(2x-pi) is 5