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midpoint
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parallel y= 4/3 xparallel domain of (5x^3)/(x^3+2x^2+5x)domain inverse of f(x)= 1/(x^3)inverse extreme 5x^3-15xextreme points extreme f(x)=x^2-4xextreme points
Frequently Asked Questions (FAQ)
What is the midpoint (1,-5),(-7,7) ?
The midpoint (1,-5),(-7,7) is (-3,1)