What is the domain of f(x)=((sqrt(x-2)))/(x-3) ?

The domain of f(x)=((sqrt(x-2)))/(x-3) is 2 3

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domain of f(x)=((sqrt(x-2)))/(x-3)

domain

f (x) = \frac{( x - 2 )}{x - 3}

2 \leq x < 3 or x > 3

Interval Notation

Solution steps

Find non-negative values for radicals:

x \geq 2

Find undefined (singularity) points:

x = 3

Combine real regions and undefined points for final function domain

2 \leq x < 3 or x > 3

y = 5 csc (8 x^{4} - 2 x + 1)

f (x) = \frac{- x ^{2} + 4 x - 1}{x - 2}

f (x) = - 2 x^{2} + 16 x - 15

f (x) = - \frac{1}{2 4 - x}

f (x) = \frac{( 9 x - 6 )}{x + 9}

What is the domain of f(x)=((sqrt(x-2)))/(x-3) ?
The domain of f(x)=((sqrt(x-2)))/(x-3) is 2<= x<3\lor x>3