What is the inverse of (sqrt(pi))/(3x^{3/2)} ?

The inverse of (sqrt(pi))/(3x^{3/2)} is cube root of pi/(9x^2)

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inverse of (sqrt(pi))/(3x^{3/2)}

inverse

\frac{π}{3 x ^{\frac{3}{2}}}

3 \frac{π}{9 x ^{2}}

Solution steps

y = \frac{π}{3 x ^{\frac{3}{2}}}

Replace

x

with

y

x = \frac{π}{3 y ^{\frac{3}{2}}}

Solve for

y, x = \frac{π}{3 y ^{\frac{3}{2}}}

3 \frac{π}{9 x ^{2}}

y = \frac{5}{4} x

y = - \frac{3}{2} x - 1, (4, 6)

f (x) = \frac{1}{x ^{2}} + 4

f (x) = tan (\frac{x}{8 x ^{2} + 3})

f (x) = 9 x + 12

What is the inverse of (sqrt(pi))/(3x^{3/2)} ?
The inverse of (sqrt(pi))/(3x^{3/2)} is cube root of pi/(9x^2)