What is the extreme f(x)=-x^3+3x^2-2 ?

The extreme f(x)=-x^3+3x^2-2 is Minimum(0,-2),Maximum(2,2)

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extreme f(x)=-x^3+3x^2-2

extreme points

f (x) = - x^{3} + 3 x^{2} - 2

Minimum (0, - 2), Maximum (2, 2)

Solution steps

f^{'} (x) = - 3 x^{2} + 6 x

Find intervals:

Decreasing

: - \infty < x < 0,

Increasing

: 0 < x < 2,

Decreasing

: 2 < x < \infty

Plug

x = 0

into

- x^{3} + 3 x^{2} - 2 : - 2

Minimum (0, - 2)

Plug

x = 2

into

- x^{3} + 3 x^{2} - 2 : 2

Maximum (2, 2)

Minimum (0, - 2), Maximum (2, 2)

26 sin (0.5 x - 2) + 68

f (x) = 17

f (x) = \frac{4 x - 3}{6 - 3 x}

cos (x + \frac{π}{2})

f (x) = \frac{x ^{2} - 5 x - 6}{x ^{2} - 2 x - 3}

What is the extreme f(x)=-x^3+3x^2-2 ?
The extreme f(x)=-x^3+3x^2-2 is Minimum(0,-2),Maximum(2,2)