What is the inverse of f(x)=x^2+3x ?

The inverse of f(x)=x^2+3x is (-3+sqrt(9+4x))/2 ,(-3-sqrt(9+4x))/2

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inverse of f(x)=x^2+3x

inverse

f (x) = x^{2} + 3 x

\frac{- 3 + 9 + 4 x}{2}, \frac{- 3 - 9 + 4 x}{2}

Solution steps

y = x^{2} + 3 x

Replace

x

with

y

x = y^{2} + 3 y

Solve for

y, x = y^{2} + 3 y

\frac{- 3 + 9 + 4 x}{2}, \frac{- 3 - 9 + 4 x}{2}

f (x) = x e^{\frac{1}{x ^{2}}}

f (x) = 6 x - 2

\frac{x ^{2}}{x ^{2} + 27}

f (x) = \frac{1}{x ^{2} + x + 3}

What is the inverse of f(x)=x^2+3x ?
The inverse of f(x)=x^2+3x is (-3+sqrt(9+4x))/2 ,(-3-sqrt(9+4x))/2