What is the inverse of ((2x-1))/(2x+5) ?

The inverse of ((2x-1))/(2x+5) is (-1-5x)/(2(-1+x))

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inverse of ((2x-1))/(2x+5)

inverse

\frac{( 2 x - 1 )}{2 x + 5}

\frac{- 1 - 5 x}{2 ( - 1 + x )}

Solution steps

y = \frac{2 x - 1}{2 x + 5}

Replace

x

with

y

x = \frac{2 y - 1}{2 y + 5}

Solve for

y, x = \frac{2 y - 1}{2 y + 5}

\frac{- 1 - 5 x}{2 ( - 1 + x )}

f (x) = - x^{4}

f (x) = \frac{( x - 9 )}{( x + 9 )}

2 x - y = 5

f (x) = \frac{x + 1}{x ^{2} - 4 x - 12}

(\frac{3}{2}, - 2), (\frac{- 1}{2}, 0)

What is the inverse of ((2x-1))/(2x+5) ?
The inverse of ((2x-1))/(2x+5) is (-1-5x)/(2(-1+x))