What is the inverse of y=(2x)/(x^2+49) ?

The inverse of y=(2x)/(x^2+49) is (1+sqrt(-49x^2+1))/x ,(1-sqrt(-49x^2+1))/x

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of y=(2x)/(x^2+49)

inverse

y = \frac{2 x}{x ^{2} + 49}

\frac{1 + - 49 x ^{2} + 1}{x}, \frac{1 - - 49 x ^{2} + 1}{x}

Solution steps

y = \frac{2 x}{x ^{2} + 49}

Replace

x

with

y

x = \frac{2 y}{y ^{2} + 49}

Solve for

y, x = \frac{2 y}{y ^{2} + 49}

\frac{1 + - 49 x ^{2} + 1}{x}, \frac{1 - - 49 x ^{2} + 1}{x}

f (x) = 4 x^{3} - 6 x^{2} + 3 x - 1

f (x) = \frac{( 7 x + 1 )}{x - 3}

y = - \frac{4}{5} x + 4

f (x) = \frac{( \frac{x}{5} )}{( \frac{x}{5} ) + 5}

3 x

What is the inverse of y=(2x)/(x^2+49) ?
The inverse of y=(2x)/(x^2+49) is (1+sqrt(-49x^2+1))/x ,(1-sqrt(-49x^2+1))/x