What is the domain of f(x)= 1/(sqrt(8x-16)) ?

The domain of f(x)= 1/(sqrt(8x-16)) is x>2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of f(x)= 1/(sqrt(8x-16))

domain

f (x) = \frac{1}{8 x - 16}

x > 2

Interval Notation

(2, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 2

Find undefined (singularity) points:

x = 2

Combine real regions and undefined points for final function domain

x > 2

5 x^{4} + 20 x^{3}

f (x) = 2^{x + 3}

\frac{1}{3} x^{3} + 2 x^{2} - 5 x + \frac{8}{3}

f (x) = (2 x + 3)^{4} (x - 3)^{5}

(2, - 73), (62, - 33)

What is the domain of f(x)= 1/(sqrt(8x-16)) ?
The domain of f(x)= 1/(sqrt(8x-16)) is x>2