What is the inverse of f(x)=(4x+3)/(1-8x) ?

The inverse of f(x)=(4x+3)/(1-8x) is -(3-x)/(4(1+2x))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of f(x)=(4x+3)/(1-8x)

inverse

f (x) = \frac{4 x + 3}{1 - 8 x}

- \frac{3 - x}{4 ( 1 + 2 x )}

Solution steps

y = \frac{4 x + 3}{1 - 8 x}

Replace

x

with

y

x = \frac{4 y + 3}{1 - 8 y}

Solve for

y, x = \frac{4 y + 3}{1 - 8 y}

- \frac{3 - x}{4 ( 1 + 2 x )}

f (x) = (x - 9)^{2}

16 - (20 x + 15)^{2}

\frac{x ^{2}}{x - 1}

h (x) = 5 (x - 9)

\frac{x}{2 x ^{2} + 4}

What is the inverse of f(x)=(4x+3)/(1-8x) ?
The inverse of f(x)=(4x+3)/(1-8x) is -(3-x)/(4(1+2x))