What is the midpoint (-5/2 , 1/2),(-15/2 ,-13/2) ?

The midpoint (-5/2 , 1/2),(-15/2 ,-13/2) is (-5,-3)

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midpoint (-5/2 , 1/2),(-15/2 ,-13/2)

midpoint

(- \frac{5}{2}, \frac{1}{2}), (- \frac{15}{2}, - \frac{13}{2})

(- 5, - 3)

Solution steps

Midpoint of

(x_{1}, y_{1}), (x_{2}, y_{2})

(\frac{x _{2} + x _{1}}{2}, \frac{y _{2} + y _{1}}{2})

(x_{1}, y_{1}) = (- \frac{5}{2}, \frac{1}{2}), (x_{2}, y_{2}) = (- \frac{15}{2}, - \frac{13}{2})

= (\frac{- \frac{15}{2} - \frac{5}{2}}{2}, \frac{- \frac{13}{2} + \frac{1}{2}}{2})

Refine

= (- 5, - 3)

f (x) = 3 x^{\frac{2}{3}} - 2 x

4 - x^{2}

tan (x) (sec (x))^{4}

2 x + 18 y - 9 = 0

What is the midpoint (-5/2 , 1/2),(-15/2 ,-13/2) ?
The midpoint (-5/2 , 1/2),(-15/2 ,-13/2) is (-5,-3)