What is the extreme \sqrt[3]{x}(x+4) ?

The extreme \sqrt[3]{x}(x+4) is Minimum(-1,-3)

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extreme \sqrt[3]{x}(x+4)

extreme points

Minimum (- 1, - 3)

Solution steps

Find the critical points:

x = - 1, x = 0

Domain of

Find intervals:

Decreasing

: - \infty < x < - 1,

Increasing

: - 1 < x < 0,

Increasing

: 0 < x < \infty

Plug the extreme point

x = - 1

into

Minimum (- 1, - 3)

f (x) = 3 x^{\frac{2}{3}} - 2 x

4 - x^{2}

tan (x) (sec (x))^{4}

2 x + 18 y - 9 = 0

f (x) = \frac{e ^{x}}{x - 4}

What is the extreme \sqrt[3]{x}(x+4) ?
The extreme \sqrt[3]{x}(x+4) is Minimum(-1,-3)