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Popular >

extreme f(x)=(e^x)/(x-4)

Solution

extreme points

f (x) = \frac{e ^{x}}{x - 4}

Solution

Minimum (5, e^{5})

Solution steps

f^{'} (x) = \frac{e ^{x} x - 5 e ^{x}}{( x - 4 ) ^{2}}

Find intervals:

Decreasing

: - \infty < x < 4,

Decreasing

: 4 < x < 5,

Increasing

: 5 < x < \infty

Plug

x = 5

into

\frac{e ^{x}}{x - 4} : e^{5}

Minimum (5, e^{5})

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domain of h(x)=sqrt(2x-5)domain

h (x) = 2 x - 5

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domain of 2sqrt(x+4)-1 domain

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Frequently Asked Questions (FAQ)

What is the extreme f(x)=(e^x)/(x-4) ?
The extreme f(x)=(e^x)/(x-4) is Minimum(5,e^5)