What is the domain of h(x)=sqrt(2x-5) ?

The domain of h(x)=sqrt(2x-5) is x>= 5/2

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domain of h(x)=sqrt(2x-5)

domain

h (x) = 2 x - 5

x \geq \frac{5}{2}

Interval Notation

[\frac{5}{2}, \infty)

Solution steps

Find non-negative values for radicals:

x \geq \frac{5}{2}

The function domain

x \geq \frac{5}{2}

f (x) = tan (x - \frac{π}{4})

2 x + 4 - 1

81 - x^{4}

f (x) = 0.05 x + 20 + \frac{125}{x}

4 x - y = - 1

What is the domain of h(x)=sqrt(2x-5) ?
The domain of h(x)=sqrt(2x-5) is x>= 5/2