What is the critical f(x)=4x^2(5^x) ?

The critical f(x)=4x^2(5^x) is x=-2/(ln(5)),x=0

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critical f(x)=4x^2(5^x)

critical points

f (x) = 4 x^{2} (5^{x})

x = - \frac{2}{ln ( 5 )}, x = 0

Solution steps

4 x^{2} \cdot 5^{x}

Find where

f^{'} (x)

is equal to zero or undefined

x = - \frac{2}{ln ( 5 )}, x = 0

Identify critical points not in

f (x)

domain

Domain of

4 x^{2} 5^{x} : - \infty < x < \infty

All critical points are in domain

x = - \frac{2}{ln ( 5 )}, x = 0

f (x) = x^{3} - 3 x^{2} + 8

(6, 5), (2, 0)

f (x) = 2 x^{4} - 8 x^{3}

f (x) = - 5 x^{2} + 40 x

y = x^{2} - x - 42

What is the critical f(x)=4x^2(5^x) ?
The critical f(x)=4x^2(5^x) is x=-2/(ln(5)),x=0