What is the extreme f(x)=3x^3-9x+1 ?

The extreme f(x)=3x^3-9x+1 is Maximum(-1,7),Minimum(1,-5)

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extreme f(x)=3x^3-9x+1

extreme points

f (x) = 3 x^{3} - 9 x + 1

Maximum (- 1, 7), Minimum (1, - 5)

Solution steps

f^{'} (x) = 9 x^{2} - 9

Find intervals:

Increasing

: - \infty < x < - 1,

Decreasing

: - 1 < x < 1,

Increasing

: 1 < x < \infty

Plug

x = - 1

into

3 x^{3} - 9 x + 1 : 7

Maximum (- 1, 7)

Plug

x = 1

into

3 x^{3} - 9 x + 1 : - 5

Minimum (1, - 5)

Maximum (- 1, 7), Minimum (1, - 5)

f (x) = - 4 x^{2} + 6 x + 1

f (x) = x^{3} e^{x}

sin (2 x)

3 x - 4 y = - 12

(7, 1), (16, - 12)

What is the extreme f(x)=3x^3-9x+1 ?
The extreme f(x)=3x^3-9x+1 is Maximum(-1,7),Minimum(1,-5)