What is the domain of f(x)= 1/((x-8)^2)+9 ?

The domain of f(x)= 1/((x-8)^2)+9 is x 8

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domain of f(x)= 1/((x-8)^2)+9

domain

f (x) = \frac{1}{( x - 8 ) ^{2}} + 9

x < 8 or x > 8

Interval Notation

(- \infty, 8) \cup (8, \infty)

Solution steps

Find undefined (singularity) points:

x = 8

The function domain

x < 8 or x > 8

6 x + 2

f (x) = 6 x + 6

16 - x^{2}

f (x) = \frac{( x - 5 )}{4}

What is the domain of f(x)= 1/((x-8)^2)+9 ?
The domain of f(x)= 1/((x-8)^2)+9 is x<8\lor x>8