What is the intercepts of f(x)=-x^2-4x+1 ?

The intercepts of f(x)=-x^2-4x+1 is X Intercepts: (-2-sqrt(5),0),(sqrt(5)-2,0),Y Intercepts: (0,1)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

intercepts of f(x)=-x^2-4x+1

intercepts

f (x) = - x^{2} - 4 x + 1

X Intercepts : (- 2 - 5, 0), (5 - 2, 0), Y Intercepts : (0, 1)

Solution steps

x -

axis interception points of

- x^{2} - 4 x + 1 : (- 2 - 5, 0), (5 - 2, 0)

y -

axis interception point of

- x^{2} - 4 x + 1 : (0, 1)

X Intercepts : (- 2 - 5, 0), (5 - 2, 0), Y Intercepts : (0, 1)

\frac{3 x + 4}{x ^{2} - 25}

f (x) = \frac{4 x + 5}{x + 4}

\frac{1}{1 + \frac{1}{1 + \frac{1}{x}}}

\frac{x ^{3} + 2 x ^{2} + x}{x ^{2} + 3 x + 2}

f (x) = \frac{6 x}{x + 5}

What is the intercepts of f(x)=-x^2-4x+1 ?
The intercepts of f(x)=-x^2-4x+1 is X Intercepts: (-2-sqrt(5),0),(sqrt(5)-2,0),Y Intercepts: (0,1)