What is the inverse of 1/(1+\frac{1){1+1/x}} ?

The inverse of 1/(1+\frac{1){1+1/x}} is (1-x)/(2x-1)

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inverse of 1/(1+\frac{1){1+1/x}}

inverse

\frac{1}{1 + \frac{1}{1 + \frac{1}{x}}}

\frac{1 - x}{2 x - 1}

Solution steps

y = \frac{1}{1 + \frac{1}{1 + \frac{1}{x}}}

Replace

x

with

y

x = \frac{1}{1 + \frac{1}{1 + \frac{1}{y}}}

Solve for

y, x = \frac{1}{1 + \frac{1}{1 + \frac{1}{y}}}

\frac{1 - x}{2 x - 1}

\frac{x ^{3} + 2 x ^{2} + x}{x ^{2} + 3 x + 2}

f (x) = \frac{6 x}{x + 5}

g (x) = \frac{( x ^{2} + 3 x + 2 )}{( x + 1 )}

\frac{( x - 3 )}{x ^{2} - 4 x - 12}

f (x) = x - 8

What is the inverse of 1/(1+\frac{1){1+1/x}} ?
The inverse of 1/(1+\frac{1){1+1/x}} is (1-x)/(2x-1)