What is the perpendicular 3x-4y=15 ?

The perpendicular 3x-4y=15 is y=-4/3 x+b

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perpendicular 3x-4y=15

perpendicular

3 x - 4 y = 15

y = - \frac{4}{3} x + b

Solution steps

Find the slope of

3 x - 4 y = 15 : m = \frac{3}{4}

Compute the slope of the perpendicular line:

m_{p} = - \frac{4}{3}

Line with slope m=

- \frac{4}{3} : y = - \frac{4}{3} x + b

y = - \frac{4}{3} x + b

f (x) = \frac{( 0.35 x + 3 )}{( 0.25 x + 8 )}

f (x) = \frac{7 - x}{x ^{2} + 1}

- 2 x + 5 y = - 30

2 x^{3} - 12 x^{2} + 10 x + 10

\frac{x - 5}{8 x + 4}