What is the perpendicular 3x+6y=12,\at ?

The perpendicular 3x+6y=12,\at is y=2x+b

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perpendicular 3x+6y=12,\at

perpendicular

3 x + 6 y = 12, at

y = 2 x + b

Solution steps

Find the slope of

3 x + 6 y = 12 : m = - \frac{1}{2}

Compute the slope of the perpendicular line:

m_{p} = 2

Line with slope m=

2 : y = 2 x + b

y = 2 x + b

(2, 4), (5, - 4)

\frac{ln ( x )}{x ^{2}}

f (x) = cos (2 x + π)

9 - x^{2}

\frac{3}{x - 1}

What is the perpendicular 3x+6y=12,\at ?
The perpendicular 3x+6y=12,\at is y=2x+b