What is the extreme f(x)=3x^4+4x^3 ?

The extreme f(x)=3x^4+4x^3 is Minimum(-1,-1),Saddle(0,0)

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extreme f(x)=3x^4+4x^3

extreme points

f (x) = 3 x^{4} + 4 x^{3}

Minimum (- 1, - 1), Saddle (0, 0)

Solution steps

f^{'} (x) = 12 x^{3} + 12 x^{2}

Find intervals:

Decreasing

: - \infty < x < - 1,

Increasing

: - 1 < x < 0,

Increasing

: 0 < x < \infty

Plug

x = - 1

into

3 x^{4} + 4 x^{3} : - 1

Minimum (- 1, - 1)

Plug

x = 0

into

3 x^{4} + 4 x^{3} : 0

Saddle (0, 0)

Minimum (- 1, - 1), Saddle (0, 0)

y = - 2 (x - 12.5) + 5

x^{2} - 10

f (x) = 3

f (x) = \frac{( x ^{2} + 2 x - 3 )}{x - 1}

f (x) = (\frac{2 x ^{2}}{2 x + 4})

What is the extreme f(x)=3x^4+4x^3 ?
The extreme f(x)=3x^4+4x^3 is Minimum(-1,-1),Saddle(0,0)