What is the domain of x/(1-ln(x-9)) ?

The domain of x/(1-ln(x-9)) is 9 e+9

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domain of x/(1-ln(x-9))

domain

\frac{x}{1 - ln ( x - 9 )}

9 < x < e + 9 or x > e + 9

Interval Notation

(9, e + 9) \cup (e + 9, \infty)

Solution steps

Find positive values for logs:

x > 9

Find undefined (singularity) points:

x = e + 9

Combine real regions and undefined points for final function domain

9 < x < e + 9 or x > e + 9

f (x) = 4 x^{3} - 6 x^{2} + 7 x - 8

f (x) = - 8 x + 16

f (x) = x^{2} - x + 2

f (x) = \frac{3 x - 4}{2 x + 11}

f (x) = \frac{x ^{2} - 4 x + 3}{x - 1}

What is the domain of x/(1-ln(x-9)) ?
The domain of x/(1-ln(x-9)) is 9<x<e+9\lor x>e+9