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Popular >

distance (4,10),(8,7)

Solution

distance

(4, 10), (8, 7)

Solution

5

Solution steps

The distance between

(x_{1}, y_{1}), (x_{2}, y_{2})

is:

(x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}

The distance between

(4, 10)

and

(8, 7)

is

= (8 - 4)^{2} + (7 - 10)^{2}

Simplify

= 5

Popular Examples

domain of x/(x^2+3x+2)domain

\frac{x}{x ^{2} + 3 x + 2}

asymptotes of sqrt(x)asymptotes

x

critical f(x)=6sqrt(x)-6x critical points

f (x) = 6 x - 6 x

symmetry y= 1/2 (x-3)^2+5 symmetry

y = \frac{1}{2} (x - 3)^{2} + 5

intercepts of f(x)=-x^2+3x+4 intercepts

f (x) = - x^{2} + 3 x + 4

Frequently Asked Questions (FAQ)

What is the distance (4,10),(8,7) ?
The distance (4,10),(8,7) is 5