What is the inverse of f(x)=\sqrt[3]{6x-7} ?

The inverse of f(x)=\sqrt[3]{6x-7} is (x^3+7)/6

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inverse of f(x)=\sqrt[3]{6x-7}

inverse

\frac{x ^{3} + 7}{6}

Solution steps

Replace

x

with

y

Solve for

\frac{x ^{3} + 7}{6}

f (x) = \frac{9 x ^{2} + 36 x + 41}{3 x + 5}

f (x) = 2 tan (π x)

f (x) = (x - 15)^{2}, x \leq 15

f (x) = 20 x^{3}

x^{2} - 2 x + 5

What is the inverse of f(x)=\sqrt[3]{6x-7} ?
The inverse of f(x)=\sqrt[3]{6x-7} is (x^3+7)/6