What is the range of f(x)=9+(8+x)^{1/2} ?

The range of f(x)=9+(8+x)^{1/2} is f(x)>= 9

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range of f(x)=9+(8+x)^{1/2}

range

f (x) = 9 + (8 + x)^{\frac{1}{2}}

f (x) \geq 9

Interval Notation

[9, \infty)

Solution steps

The range of an radical function of the form

c a x + b + k

f (x) \geq k

k = 9

f (x) \geq 9

f (x) = 3 x^{2} + x - 2

f (x) = x^{3} + 2 x^{2} - 4 x - 8

f (x) = 5 + 2 - x

\frac{10 x ^{2} + x - 10}{x ^{2} - 1}

f (x) = \frac{( x + 7 )}{x - 3}

What is the range of f(x)=9+(8+x)^{1/2} ?
The range of f(x)=9+(8+x)^{1/2} is f(x)>= 9