What is the domain of f(x)=((x-1)^2)/(x^3-2x^2+x) ?

The domain of f(x)=((x-1)^2)/(x^3-2x^2+x) is x 1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of f(x)=((x-1)^2)/(x^3-2x^2+x)

domain

f (x) = \frac{( x - 1 ) ^{2}}{x ^{3} - 2 x ^{2} + x}

x < 0 or 0 < x < 1 or x > 1

Interval Notation

(- \infty, 0) \cup (0, 1) \cup (1, \infty)

Solution steps

Find undefined (singularity) points:

x = 0, x = 1

The function domain

x < 0 or 0 < x < 1 or x > 1

f (x) = 2 (x + 3)^{2} + 4

f (x) = x^{3} + 5 x^{2} - 2 x + 10

f (x) = \frac{x ^{3}}{x - 2}

f (x) = 5 csc (\frac{1}{2} π x - \frac{1}{6} π)

f (x) = \frac{x ( x - 2 ) ^{2}}{( x + 5 ) ^{3}}

What is the domain of f(x)=((x-1)^2)/(x^3-2x^2+x) ?
The domain of f(x)=((x-1)^2)/(x^3-2x^2+x) is x<0\lor 0<x<1\lor x>1