What is the domain of f(x)=(x-1)^{1/2} ?

The domain of f(x)=(x-1)^{1/2} is x>= 1

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domain of f(x)=(x-1)^{1/2}

domain

f (x) = (x - 1)^{\frac{1}{2}}

x \geq 1

Interval Notation

[1, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 1

The function domain

x \geq 1

f (x) = (x - 3) (x + 1)

h (x) = \frac{9 x ^{2} - 16}{2 ( 3 x + 4 ) ^{2}}

m = \frac{5}{3}, (- \frac{1}{2}, \frac{5}{2})

(20.1) (4.2)

f (x) = e^{2 x}

What is the domain of f(x)=(x-1)^{1/2} ?
The domain of f(x)=(x-1)^{1/2} is x>= 1