What is the domain of (u+1)/(1+1/(u+1)) ?

The domain of (u+1)/(1+1/(u+1)) is u -1

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domain of (u+1)/(1+1/(u+1))

domain

\frac{u + 1}{1 + \frac{1}{u + 1}}

u < - 2 or - 2 < u < - 1 or u > - 1

Interval Notation

(- \infty, - 2) \cup (- 2, - 1) \cup (- 1, \infty)

Solution steps

Find undefined (singularity) points:

u = - 2, u = - 1

The function domain

u < - 2 or - 2 < u < - 1 or u > - 1

y = \frac{3}{2} x, (2, 3)

- x^{2} - 36 + 6

f (x) = lo g_{2} (4 - x^{4})

f (x) = \frac{x + 3}{x - 2}

f (x) = \frac{( x - 8 )}{( x - 3 ) ( x + 5 )}

What is the domain of (u+1)/(1+1/(u+1)) ?
The domain of (u+1)/(1+1/(u+1)) is u<-2\lor-2<u<-1\lor u>-1