What is the domain of 1+(2+x)^{1/2} ?

The domain of 1+(2+x)^{1/2} is x>=-2

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domain of 1+(2+x)^{1/2}

domain

1 + (2 + x)^{\frac{1}{2}}

x \geq - 2

Interval Notation

[- 2, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - 2

The function domain

x \geq - 2

(- \frac{3}{2}, - \frac{7}{4}), (\frac{8}{5}, - \frac{10}{3})

f (x) = \frac{( x ^{2} - 3 x )}{( x ^{2} - 9 )}

f (x) = 1 - 2 lo g_{5} (x)

f (x) = - x + 1

f (x) = x^{2} - x - 2