What is the critical 1/(x^2-4x+6) ?

The critical 1/(x^2-4x+6) is x=2

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critical 1/(x^2-4x+6)

critical points

\frac{1}{x ^{2} - 4 x + 6}

x = 2

Solution steps

\frac{1}{x ^{2} - 4 x + 6}

Find where

f^{'} (x)

is equal to zero or undefined

x = 2

Identify critical points not in

f (x)

domain

Domain of

\frac{1}{x ^{2} - 4 x + 6} : - \infty < x < \infty

All critical points are in domain

x = 2

8 x + 6 y = - 60

f (x) = x^{2} + 4 x + 4

f (x) = x + 5 + 1

(x - 2) (x - 6)^{3} + 6

f (x) = x^{4} - 4 x^{3} + 8