What is the range of xsqrt(36-x^2) ?

The range of xsqrt(36-x^2) is -18<= f(x)<= 18

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range of xsqrt(36-x^2)

range

x 36 - x^{2}

- 18 \leq f (x) \leq 18

Interval Notation

[- 18, 18]

Solution steps

Find the minimum and maximum value in each defined interval and unite the results

Domain of

x 36 - x^{2} : - 6 \leq x \leq 6

Extreme Points of

x 36 - x^{2} :

Maximum

(- 6, 0),

Minimum

(- 32, - 18),

Maximum

(32, 18),

Minimum

(6, 0)

Find the range for the interval

- 6 \leq x \leq 6 : - 18 \leq f (x) \leq 18

Combine the ranges of all domain intervals to obtain the function range

- 18 \leq f (x) \leq 18

- 4 x - 12 y = 24

f (x) = x^{3} - 4 x^{2} + 5 x - 2

f (x) = \frac{25 x}{x ^{2} + 25}

f (x) = \frac{x + 3}{3 x - 27} + \frac{1}{x ^{2} - 4}

\frac{10 - x}{x ^{2} - 1}

What is the range of xsqrt(36-x^2) ?
The range of xsqrt(36-x^2) is -18<= f(x)<= 18