What is the extreme f(x)=4x^3-6x^2-72x ?

The extreme f(x)=4x^3-6x^2-72x is Maximum(-2,88),Minimum(3,-162)

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extreme f(x)=4x^3-6x^2-72x

extreme points

f (x) = 4 x^{3} - 6 x^{2} - 72 x

Maximum (- 2, 88), Minimum (3, - 162)

Solution steps

f^{'} (x) = 12 x^{2} - 12 x - 72

Find intervals:

Increasing

: - \infty < x < - 2,

Decreasing

: - 2 < x < 3,

Increasing

: 3 < x < \infty

Plug

x = - 2

into

4 x^{3} - 6 x^{2} - 72 x : 88

Maximum (- 2, 88)

Plug

x = 3

into

4 x^{3} - 6 x^{2} - 72 x : - 162

Minimum (3, - 162)

Maximum (- 2, 88), Minimum (3, - 162)

x e^{- 2 x}

y = 3 x + 17

\frac{x + 3}{x - 5}

f (x) = \frac{1}{x} - 4

x^{3} - \frac{3}{2} x^{2}

What is the extreme f(x)=4x^3-6x^2-72x ?
The extreme f(x)=4x^3-6x^2-72x is Maximum(-2,88),Minimum(3,-162)