What is the perpendicular 4y=-16x+8 ?

The perpendicular 4y=-16x+8 is y= 1/4 x+b

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perpendicular 4y=-16x+8

perpendicular

4 y = - 16 x + 8

y = \frac{1}{4} x + b

Solution steps

Find the slope of

4 y = - 16 x + 8 : m = - 4

Compute the slope of the perpendicular line:

m_{p} = \frac{1}{4}

Line with slope m=

\frac{1}{4} : y = \frac{1}{4} x + b

y = \frac{1}{4} x + b

f (x) = x^{3} - 9 x^{2}

f (x) = x^{4} - 5 x^{3} + 5 x^{2} - 3

- 0.5 x^{2} - 3

f (x) = 3 x^{6} + 7 x^{4} + 9 x

f (x) = x^{2} + 1