What is the inverse of f(x)=(8x-1)/(2x+7) ?

The inverse of f(x)=(8x-1)/(2x+7) is (-1-7x)/(2(-4+x))

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inverse of f(x)=(8x-1)/(2x+7)

inverse

f (x) = \frac{8 x - 1}{2 x + 7}

\frac{- 1 - 7 x}{2 ( - 4 + x )}

Solution steps

y = \frac{8 x - 1}{2 x + 7}

Replace

x

with

y

x = \frac{8 y - 1}{2 y + 7}

Solve for

y, x = \frac{8 y - 1}{2 y + 7}

\frac{- 1 - 7 x}{2 ( - 4 + x )}

f (x) = (x^{7} - 9)^{9}

(x - 4)^{3}

f (x) = - 42 + 19 x - 2 x^{2}

(x - 5)^{\frac{2}{3}}

f (x) = \frac{tan ( x )}{4 - x ^{2}}

What is the inverse of f(x)=(8x-1)/(2x+7) ?
The inverse of f(x)=(8x-1)/(2x+7) is (-1-7x)/(2(-4+x))