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Popular >

extreme f(x)= 9/((x^2+1))

Solution

extreme points

f (x) = \frac{9}{( x ^{2} + 1 )}

Solution

Maximum (0, 9)

Solution steps

f^{'} (x) = - \frac{18 x}{( x ^{2} + 1 ) ^{2}}

Find intervals:

Increasing

: - \infty < x < 0,

Decreasing

: 0 < x < \infty

Plug

x = 0

into

\frac{9}{x ^{2} + 1} : 9

Maximum (0, 9)

Popular Examples

asymptotes of (2x^2-6x+1)/(1+x^2)asymptotes

\frac{2 x ^{2} - 6 x + 1}{1 + x ^{2}}

critical f(x)=3x^5-5x^3+1 critical points

f (x) = 3 x^{5} - 5 x^{3} + 1

symmetry (x-3)^2-9 symmetry

(x - 3)^{2} - 9

inverse of f(x)=cos(x)inverse

f (x) = cos (x)

range of f(x)= 1/9 x^2 range

f (x) = \frac{1}{9} x^{2}

Frequently Asked Questions (FAQ)

What is the extreme f(x)= 9/((x^2+1)) ?
The extreme f(x)= 9/((x^2+1)) is Maximum(0,9)