What is the domain of f(x)=sqrt(x^2-x-6) ?

The domain of f(x)=sqrt(x^2-x-6) is x = 3

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domain of f(x)=sqrt(x^2-x-6)

domain

f (x) = x^{2} - x - 6

x \leq - 2 or x \geq 3

Interval Notation

(- \infty, - 2] \cup [3, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 2 or x \geq 3

The function domain

x \leq - 2 or x \geq 3

f (x) = x^{2} - 6 x + 5

y - 64 = - \frac{1}{6} (x - 16)

f (x) = \frac{1}{6} x

y = x + 6

f (x) = x^{3} - 9 x^{2} + 24 x - 10

What is the domain of f(x)=sqrt(x^2-x-6) ?
The domain of f(x)=sqrt(x^2-x-6) is x<=-2\lor x>= 3