What is the extreme f(x)=x^3-9x^2+24x-10 ?

The extreme f(x)=x^3-9x^2+24x-10 is Maximum(2,10),Minimum(4,6)

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extreme f(x)=x^3-9x^2+24x-10

extreme points

f (x) = x^{3} - 9 x^{2} + 24 x - 10

Maximum (2, 10), Minimum (4, 6)

Solution steps

f^{'} (x) = 3 x^{2} - 18 x + 24

Find intervals:

Increasing

: - \infty < x < 2,

Decreasing

: 2 < x < 4,

Increasing

: 4 < x < \infty

Plug

x = 2

into

x^{3} - 9 x^{2} + 24 x - 10 : 10

Maximum (2, 10)

Plug

x = 4

into

x^{3} - 9 x^{2} + 24 x - 10 : 6

Minimum (4, 6)

Maximum (2, 10), Minimum (4, 6)

2^{x} - 3.2 x

lo g_{2} (2^{x})

f (x) = \frac{1}{2} x^{2} + 8 x + 5

f (x) = 5 x

f (x) = \frac{x + 1}{x ^{2} + 8}

What is the extreme f(x)=x^3-9x^2+24x-10 ?
The extreme f(x)=x^3-9x^2+24x-10 is Maximum(2,10),Minimum(4,6)