What is the domain of f(x)=sqrt(x^2+x+4) ?

The domain of f(x)=sqrt(x^2+x+4) is -infinity <x<infinity

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domain of f(x)=sqrt(x^2+x+4)

domain

f (x) = x^{2} + x + 4

- \infty < x < \infty

Interval Notation

(- \infty, \infty)

Solution steps

Find non-negative values for radicals:

- \infty < x < \infty

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < x < \infty

f (x) = \frac{5}{x ^{2} + 5 x - 24}

f (x) = \frac{2}{3} x + 1 - 4

f (x) = \frac{( 5 x + 2 )}{x - 3}

2 y - 10 x = - 6

f (x) = \frac{10}{x ^{2} + 5}

What is the domain of f(x)=sqrt(x^2+x+4) ?
The domain of f(x)=sqrt(x^2+x+4) is -infinity <x<infinity