What is the inverse of f(x)=((2x-1))/((x+1)) ?

The inverse of f(x)=((2x-1))/((x+1)) is (-1-x)/(x-2)

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inverse of f(x)=((2x-1))/((x+1))

inverse

f (x) = \frac{( 2 x - 1 )}{( x + 1 )}

\frac{- 1 - x}{x - 2}

Solution steps

y = \frac{2 x - 1}{x + 1}

Replace

x

with

y

x = \frac{2 y - 1}{y + 1}

Solve for

y, x = \frac{2 y - 1}{y + 1}

\frac{- 1 - x}{x - 2}

f (x) = - 2 x^{3} - 3 x^{2} + 12 x + 11

f (x) = 3 x^{2} + 2

f (x) = \frac{4 x - 8}{3}

h (x) = 4^{x}

y = \frac{1}{3} x - 3

What is the inverse of f(x)=((2x-1))/((x+1)) ?
The inverse of f(x)=((2x-1))/((x+1)) is (-1-x)/(x-2)