What is the amplitude of y=2sin(1/3 x) ?

The amplitude of y=2sin(1/3 x) is 2

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amplitude of y=2sin(1/3 x)

amplitude

y = 2 sin (\frac{1}{3} x)

2

Solution steps

f (x) = 2 sin (\frac{1}{3} x), A = 2

Therefore, the amplitude |A| is

2

2

f (x) = \frac{6 x + 12}{x ^{2} + x - 12}

f (x) = - 2 (x - 1)^{2} + 3

3 y = - 9 x + 13

f (x) = 8 x^{2} + 1

x^{2} - 6 x + 8