What is the extreme f(x)=2x^3-3x^2-12x ?

The extreme f(x)=2x^3-3x^2-12x is Maximum(-1,7),Minimum(2,-20)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme f(x)=2x^3-3x^2-12x

extreme points

f (x) = 2 x^{3} - 3 x^{2} - 12 x

Maximum (- 1, 7), Minimum (2, - 20)

Solution steps

f^{'} (x) = 6 x^{2} - 6 x - 12

Find intervals:

Increasing

: - \infty < x < - 1,

Decreasing

: - 1 < x < 2,

Increasing

: 2 < x < \infty

Plug

x = - 1

into

2 x^{3} - 3 x^{2} - 12 x : 7

Maximum (- 1, 7)

Plug

x = 2

into

2 x^{3} - 3 x^{2} - 12 x : - 20

Minimum (2, - 20)

Maximum (- 1, 7), Minimum (2, - 20)

x + 2

\frac{x + 1}{∣ x ∣}

f (x) = x^{4} - 4 x^{3} + 10

f (x) = \frac{1}{2 x + 1}

f (x) = 2 x^{2} - 2

What is the extreme f(x)=2x^3-3x^2-12x ?
The extreme f(x)=2x^3-3x^2-12x is Maximum(-1,7),Minimum(2,-20)