What is the inverse of f(x)=x^2-4x+3 ?

The inverse of f(x)=x^2-4x+3 is 2+sqrt(x+1),2-sqrt(x+1)

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inverse of f(x)=x^2-4x+3

inverse

f (x) = x^{2} - 4 x + 3

2 + x + 1, 2 - x + 1

Solution steps

y = x^{2} - 4 x + 3

Replace

x

with

y

x = y^{2} - 4 y + 3

Solve for

y, x = y^{2} - 4 y + 3

2 + x + 1, 2 - x + 1

4 x^{3} - 24 x^{2} + 36 x

\frac{x - 4}{5 - x}

\frac{x ^{3} + 3 x ^{2} + 2 x}{- 4 x ^{2} + 4 x + 8}

x^{x^{x + x^{x}}}

f (x) = - 2 x^{2} - 4 x + 48

What is the inverse of f(x)=x^2-4x+3 ?
The inverse of f(x)=x^2-4x+3 is 2+sqrt(x+1),2-sqrt(x+1)