What is the inverse of f(x)=((x+3)^{1/4})/9 ?

The inverse of f(x)=((x+3)^{1/4})/9 is 6561x^4-3

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inverse of f(x)=((x+3)^{1/4})/9

inverse

f (x) = \frac{( x + 3 ) ^{\frac{1}{4}}}{9}

6561 x^{4} - 3

Solution steps

y = \frac{( x + 3 ) ^{\frac{1}{4}}}{9}

Replace

x

with

y

x = \frac{( y + 3 ) ^{\frac{1}{4}}}{9}

Solve for

y, x = \frac{( y + 3 ) ^{\frac{1}{4}}}{9}

6561 x^{4} - 3

3 x - y + y

f (x) = - y^{2}

f (x) = \frac{3}{x ^{2} - 81}

f (x) = lo g_{3} (x) + 6

f (x) = \frac{( 6 x ^{3} + 3 )}{( - 8 x ^{3} + 8 )}

What is the inverse of f(x)=((x+3)^{1/4})/9 ?
The inverse of f(x)=((x+3)^{1/4})/9 is 6561x^4-3