What is the domain of f(x)=(2x)/(sqrt(3x-1)) ?

The domain of f(x)=(2x)/(sqrt(3x-1)) is x> 1/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of f(x)=(2x)/(sqrt(3x-1))

domain

f (x) = \frac{2 x}{3 x - 1}

x > \frac{1}{3}

Interval Notation

(\frac{1}{3}, \infty)

Solution steps

Find non-negative values for radicals:

x \geq \frac{1}{3}

Find undefined (singularity) points:

x = \frac{1}{3}

Combine real regions and undefined points for final function domain

x > \frac{1}{3}

f (x) = 4 x^{2} - 2

\frac{x ^{2} + 2 x - 4}{5 x ^{4} - 2 x ^{3} - 7 x ^{2} - 39}

f (x) = x^{3} - 4

cos^{2} (x)

\frac{x ^{2} - 1}{x ^{3}}

What is the domain of f(x)=(2x)/(sqrt(3x-1)) ?
The domain of f(x)=(2x)/(sqrt(3x-1)) is x> 1/3