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Popular >

inflection f(x)=2x^3-3x^2+x

Solution

inflection points

f (x) = 2 x^{3} - 3 x^{2} + x

Solution

(\frac{1}{2}, 0)

Solution steps

f^{''} (x) = 12 x - 6

Find intervals:

Concave Downward

: - \infty < x < \frac{1}{2},

Concave Upward

: \frac{1}{2} < x < \infty

Plug

x = \frac{1}{2}

into

2 x^{3} - 3 x^{2} + x : 0

(\frac{1}{2}, 0)

Popular Examples

simplify (-6.4)(7.6)simplify

(- 6.4) (7.6)

domain of sqrt(1-x^2)+sqrt(x^2-1)domain

1 - x^{2} + x^{2} - 1

range of y=sqrt((2x-4)/3)range

y = \frac{2 x - 4}{3}

extreme f(x)=(x^2-4)^2 extreme points

f (x) = (x^{2} - 4)^{2}

perpendicular (1,6),y=-1/4 x+3 perpendicular

(1, 6), y = - \frac{1}{4} x + 3

Frequently Asked Questions (FAQ)

What is the inflection f(x)=2x^3-3x^2+x ?
The inflection f(x)=2x^3-3x^2+x is (1/2 ,0)