What is the inverse of f(x)=10x+sqrt(x+101) ?

The inverse of f(x)=10x+sqrt(x+101) is (20x+1+sqrt(40x+40401))/(200),(20x+1-sqrt(40x+40401))/(200)

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inverse of f(x)=10x+sqrt(x+101)

inverse

f (x) = 10 x + x + 101

\frac{20 x + 1 + 40 x + 40401}{200}, \frac{20 x + 1 - 40 x + 40401}{200}

Solution steps

y = 10 x + x + 101

Replace

x

with

y

x = 10 y + y + 101

Solve for

y, x = 10 y + y + 101

\frac{20 x + 1 + 40 x + 40401}{200}, \frac{20 x + 1 - 40 x + 40401}{200}

4 x - 9 y = - 68

f (x) = \frac{x}{x + 5}

f (x) = lo g_{3} (x + 6)

y = - x^{2} + 1

What is the inverse of f(x)=10x+sqrt(x+101) ?
The inverse of f(x)=10x+sqrt(x+101) is (20x+1+sqrt(40x+40401))/(200),(20x+1-sqrt(40x+40401))/(200)