What is the inverse of f(x)=x^2-8x+7 ?

The inverse of f(x)=x^2-8x+7 is 4+sqrt(x+9),4-sqrt(x+9)

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inverse of f(x)=x^2-8x+7

inverse

f (x) = x^{2} - 8 x + 7

4 + x + 9, 4 - x + 9

Solution steps

y = x^{2} - 8 x + 7

Replace

x

with

y

x = y^{2} - 8 y + 7

Solve for

y, x = y^{2} - 8 y + 7

4 + x + 9, 4 - x + 9

\frac{( x ^{2} + x )}{2}

f (x) = \frac{1}{3 + e ^{2 x}}

x^{2} - 2 x + 3

f (x) = x^{2} - 5 x

f (x) = 3 + 4 x^{2} \cdot e^{- x}

What is the inverse of f(x)=x^2-8x+7 ?
The inverse of f(x)=x^2-8x+7 is 4+sqrt(x+9),4-sqrt(x+9)