What is the domain of f(x)=sqrt(x^2-5x) ?

The domain of f(x)=sqrt(x^2-5x) is x = 5

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domain of f(x)=sqrt(x^2-5x)

domain

f (x) = x^{2} - 5 x

x \leq 0 or x \geq 5

Interval Notation

(- \infty, 0] \cup [5, \infty)

Solution steps

Find non-negative values for radicals:

x \leq 0 or x \geq 5

The function domain

x \leq 0 or x \geq 5

f (x) = 3 + 4 x^{2} \cdot e^{- x}

- 3 sin (2 x + \frac{π}{2})

f (x) = \frac{y ^{2} + 1}{y ^{2} - 2 y}

3 x^{2} - 2 x + 1

5.75 cos (12 t) + 7.88

What is the domain of f(x)=sqrt(x^2-5x) ?
The domain of f(x)=sqrt(x^2-5x) is x<= 0\lor x>= 5