What is the inverse of f(x)=10x^3-5 ?

The inverse of f(x)=10x^3-5 is cube root of (x+5)/(10)

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inverse of f(x)=10x^3-5

inverse

f (x) = 10 x^{3} - 5

Solution steps

y = 10 x^{3} - 5

Replace

x

with

y

x = 10 y^{3} - 5

Solve for

y, x = 10 y^{3} - 5

y = 500 (0.04 - x^{2})

\frac{1}{4 - x}

f (x) = \frac{2 x}{3} + 5

f (x) = \frac{1}{2 x + 3}

x e^{\frac{1}{x}}

What is the inverse of f(x)=10x^3-5 ?
The inverse of f(x)=10x^3-5 is cube root of (x+5)/(10)